If you could give me some advice that would be amazing. Thanks!

const int Apin = 2;
const int Bpin = 3;
const int Cpin = 4;
const int trigPin = 5;
const int echoPin = 6;
byte potVal;
byte lastVal[32]; // store the latest value here if it’s different
byte MIDIBuf[3];
unsigned long duration;
int controllerNumber = 0;
#define CONTROLLER_CHANGE_STATUS 0xB0

void sendMIDI(int ctlNum, int value);

void setup(void)
{
digitalWrite(trigPin, LOW);

pinMode(Apin, OUTPUT);
pinMode(Bpin, OUTPUT);
pinMode(Cpin, OUTPUT);
pinMode(echoPin, INPUT);
pinMode(trigPin, OUTPUT);

Serial.begin(9600); // MIDI
}

void loop()
{
controllerNumber = 0;

digitalWrite(trigPin, HIGH); // start trig pulse
delay(1);//for (int i = 0; i < 20; ++i);
digitalWrite(trigPin, LOW); // end trig pulse
duration = pulseIn(echoPin, HIGH); // read width of echo pulse

MIDIBuf[0] = CONTROLLER_CHANGE_STATUS;
MIDIBuf[1] = controllerNumber;
MIDIBuf[2] = duration;
Serial.write(MIDIBuf, 3);

for (int i = 0 ; i < 8; ++i)
{
digitalWrite(Apin, (i & 1));
digitalWrite(Bpin, (i & 2));
digitalWrite(Cpin, (i & 4));

for (int analogPin = 0; analogPin >3)&0x7F; // force 7-bit
controllerNumber++;
if (lastVal[controllerNumber] != potVal)
Serial.println(analogRead(0));
delay(100);
{ // only send if changed
lastVal[controllerNumber] = potVal;
MIDIBuf[0] = CONTROLLER_CHANGE_STATUS;
MIDIBuf[1] = controllerNumber;
MIDIBuf[2] = potVal;
Serial.write(MIDIBuf, 3);
}
}
}
}

Sorry I missed your question back on September. For more than 8 analogue inputs, there are two solutions I can think of. One would be to use two multiplexer ICs on 2 separate arduino pins, or more simply if you really only need 10 inputs, run 8 through the multiplexer and the last two through 2 standard arduino analogue inputs.

a

What additionalo IC to use for this?

Thanks,

Dave

hope this helps, a

There were some syntax errors in your code, but the following, assuming your hardware is wired up correctly, should work for you to read all 8 analog inputs of the 4051 from analog pin 0 on the arduino. If you wanted to read from 3 4051s then you just need to repeat the process in the loop, but using two other analog pins on the arduino..


void setup()

}


The loop function “void loop()” is where the guts of any arduino code goes. It simply loops through its instructions continually while the arduino is powered up.

So what you need to do is hook up all 8 piezos using the input pins of the multiplexer, then in the loop function read each of these pins in turn. (by setting s0, s1 & s2 to high or low according to what pin you are up to reading)

You cannot, in reality, read all of the 8 pins at once, you need to run through them in turn, but you do it fast enough that it makes no real difference to the user.

basically what you will be doing to the code above is adding 6 more code segments like the following but changing the LOW and HIGHS and also changing the variable name for each to make it unique (ie: readInTwo). This will switch through the inputs reading them in turn. If it seems laggy i would try removing or shortening the delay

digitalWrite(8, LOW);

digitalWrite(9, HIGH);

digitalWrite(10, LOW);

delay(10);

int readInTwo= analogRead(0); //change this variable name to be unique for each pin

//do some stuff with the value you just got

hope this helps
andrew